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x^2+10x-84.28=0
a = 1; b = 10; c = -84.28;
Δ = b2-4ac
Δ = 102-4·1·(-84.28)
Δ = 437.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{437.12}}{2*1}=\frac{-10-\sqrt{437.12}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{437.12}}{2*1}=\frac{-10+\sqrt{437.12}}{2} $
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